
Step-by-step solution-:

The area of a triangle is given by:
A=\frac{1}{2}(b h)
Where b is the base of a triangle and h is the height of the triangle.
Differentiate on both sides with respect to t:
\textcolor{primary}{\frac{d}{dt}}(A)=\textcolor{primary}{\frac{d}{dt}}(\frac{1}{2}b h)
By The Product Rule for Derivatives:
{\frac{d}{dt}}(A)=\frac{1}{2}\left({(\textcolor{secondary}{h})\frac{d}{dt}}(\textcolor{primary}{b})+(\textcolor{primary}{b}){\frac{d}{dt}}(\textcolor{secondary}{h)}\right)
The base of the triangle is decreasing:
It means
\frac{d}{dt}{({b})}={-13}
\frac{d}{dt}{(\textcolor{primary}{b})}=\textcolor{primary}{-13}, {\frac{d}{dt}}(\textcolor{secondary}{h)}=\textcolor{secondary}{6},\textcolor{primary}{b=5} ,\textcolor{secondary}{h=1}
After substituting the above expression we get:
{\frac{d}{dt}}(A)=\frac{1}{2}\left({(\textcolor{secondary}{1})}(\textcolor{primary}{-13})+(\textcolor{primary}{5}){}(\textcolor{secondary}{6)}\right)\implies {\frac{d}{dt}}(A)=\frac{17}{2}=8.5
The required rate of change of the area of a triangle is:
{\frac{d}{dt}}(A)=8.5~square~millimeters ~per~minute
You may be like this post:
Hi, if you have a question ask me.