Estimate the instantaneous rate of growth in 2004 by taking the average of two average rates of change. what are its units.

Estimate the instantaneous rate of growth in 2004 by taking the average of two average rates of change.

Step-by-step solution-:

The average growth rate is given by:

\frac{f(x_{2})-f(x_{1})}{x_{2}-x_{1}}

Instantaneous Rate of growth in 2004 is equal to average

Growth rate of 2002 and 2006:

Substitute x2=2006 and x1=2002 into the expression:

\frac{f(2006)-f(2002)}{2006-2002}

Substitute f(2006)=12440 and f(2002)=5886 into the expression:

\frac{12440-5886}{2006-2002}

After simplifying we get

1638.5

The average growth rate is given by:

1638.5~\text{locations per year}

The Instantaneous rate of growth in \textcolor{primary}{2004} is:

\textcolor{primary}{1638.5~\text{locations per year}}
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